(X^2)+10x+(5x+36)=360

Solution for (X^2)+10x+(5x+36)=360 equation:

(X^2)+10X+(5X+36)=360

We move all terms to the left:

(X^2)+10X+(5X+36)-(360)=0

We get rid of parentheses

X^2+10X+5X+36-360=0

We add all the numbers together, and all the variables

X^2+15X-324=0

a = 1; b = 15; c = -324;
Δ = b2-4ac
Δ = 152-4·1·(-324)
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1521}=39$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-39}{2*1}=\frac{-54}{2}
=-27
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+39}{2*1}=\frac{24}{2}
=12
$